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黄芩素和黄芩苷抗氧化活性的密度泛函理论研究
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摘要
黄芩素是黄芩苷的初级代谢产物,二者的分子结构差别仅在于7-位取代基,前者为酚羟基而后者为糖苷。本文采用密度泛函理论B3LYP方法在6-31G(d,p)水平上对黄芩素和黄芩苷进行了优化计算,从分子的几何结构、酚羟基氢原子上的NBO电荷、酚羟基解离能、HOMO和LUMO能级以及其能级差△E(LUMO-HOMO)等方面分析了两种化合物清除自由基的活性。C5位的酚羟基为黄芩素和黄芩苷的最大可能活性位点,C7位酚羟基也具有一定的活性,可以增加分子本身的抗氧化活性。C5位或C7位上酚羟基氢原子带正电荷越大、酚羟基的解离能越小、E(LUMO-HOMO)越小、HOMO能级相对越高,分子的抗氧化活性越高。糖苷取代C7位酚羟基上的H原子,可以提高HOMO、LUMO的轨道能级,但是分子失去了7位酚羟基,从而降低了黄芩苷分子的抗氧化活性。结果表明,黄芩素的抗氧化活性大于黄芩苷的抗氧化活性。
Baicalein, a primary metabolite of baicalin, differs from its mother compound merely by the 7-substituent(i.e.it possesses a phenolic hydroxyl(7-OH) instead o f a glucuronic acid).The molecular structures of baicalein and baicalin are calculated by using the Density Functional Theory B3 LYP method with 6-31G( d,p) basis set.It is found that the more positive charge on H atom of C5-OH or C7-OH,the lower bond dissociation energy of the hydroxyl,the higher energy level of the HOMO and the smaller △E( LUMO-HOMO) are of benefit to the antioxidant activity of baicalein and baicalin.The C5-OH is the highest active site of baicalein and baicalin,while the C7-OH is also an active site but possessing lower activity relatively.The substitution of the H atom of C7-OH by glucoside decreases the antioxidant activity for losing the phenolic hydroxyl in baicalin.
引文
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