Pulse-shape discrimination and energy quenching of alpha particles in Cs₂LiLaBr₆:Ce³⁺

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• 作者：K.E. Mesick ; ^{kmesick@lanl.gov" class="auth_mail" title="E-mail the corresponding author} ; D.D.S. Coupland ; L.C. Stonehill
• 关键词：Elpasolite ; Scintillators ; Pulse shape discrimination ; Alpha background ; Actinium contamination ; Alpha quenching
• 刊名：Nuclear Instruments and Methods in Physics Research Section A: Accelerators, Spectrometers, Detectors and Associated Equipment
• 出版年：2017
• 出版时间：1 January 2017
• 年：2017
• 卷：841
• 期：Complete
• 页码：139-143
• 全文大小：781 K

文摘

Cs₂LiLaBr₆:Ce³⁺(CLLB) is an elpasolite scintillator that offers excellent linearity and gamma-ray energy resolution and sensitivity to thermal neutrons with the ability to perform pulse-shape discrimination (PSD) to distinguish gammas and neutrons. Our investigation of CLLB has indicated the presence of intrinsic radioactive alpha background that we have determined to be from actinium contamination of the lanthanum component. We measured the pulse shapes for gamma, thermal neutron, and alpha events and determined that PSD can be performed to separate the alpha background with a moderate figure of merit of 0.98. We also measured the electron-equivalent-energy of the alpha particles in CLLB and simulated the intrinsic alpha background from ²²⁷Ac to determine the quenching factor of the alphas. A linear quenching relationship 8900216310725&_mathId=si0004.gif&_user=111111111&_pii=S0168900216310725&_rdoc=1&_issn=01689002&md5=dbedc1d04e6e26a197e03596a00b95ad" title="Click to view the MathML source">L_α=E_α×q+L₀$L_{\alpha }=E_{\alpha }\times q+L_0$ was found at alpha particle energies above 5 MeV, with a quenching factor 8900216310725&_mathId=si0005.gif&_user=111111111&_pii=S0168900216310725&_rdoc=1&_issn=01689002&md5=3a2702aa1953c3f3d7ca13e6cca977e5">8900216310725-si0005.gif">$q=0.71\mathrm{MeVee}/\mathrm{MeV}$ and an offset 8900216310725&_mathId=si0006.gif&_user=111111111&_pii=S0168900216310725&_rdoc=1&_issn=01689002&md5=66869f956dad4cfddb2ff586007e50bd">8900216310725-si0006.gif">$L_0=-1.19\mathrm{MeVee}$.