Synthesis and Characterization of R2BiCl and RBiCl2 [R = CH(SiMe3)2]
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文摘
Reaction of RLi [R = CH(SiMe3)2] with BiCl3 in a 2:1 ratio gives R2BiCl (1). RBiPh2 isformed by the action of RMgCl on Ph2BiCl. Reaction of RBiPh2 with HCl in CHCl3 givesRBiCl2 (2), which crystallizes from diethyl ether as the solvate 2·0.5Et2O. The crystalstructures of 1 and 2·0.5Et2O have been determined by X-ray diffraction. Crystals of 1 consistof pyramidal R2BiCl molecules, whereas in crystals of 2·0.5Et2O there are journals/orgnd7/18/i03/eqn/om9806444e10001.gif">{[RBi(Cl)Cl]2·Et2O}x chains with chloro bridges. The diethyl ether molecules are weakly associatedto neighboring bismuth atoms in the chain.

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