Thermodynamic analysis of hydrogen production for fuel cells from oxidative steam reforming of methanol
- 作者：Jihui Wanga ; b ; Hong Chena ; c ; Ye Tiana ; Mingfa Yaoc ; Yongdan Lia ; b ; ydli@tju.edu.cn
- 关键词：Methanol ; Oxidative steam reforming ; Hydrogen production ; Thermodynamics
- 刊名：Fuel
- 出版年：2012
- 期刊代码：33_00162361
- 类别：ce
- 出版时间：July, 2012
- 卷：97
- 期：Complete
- 页码：805-811
- 文件大小：370 K
摘要
A thermodynamic analysis of hydrogen production from oxidative steam reforming (OSR) of methanol has been carried out by a Gibbs free energy minimization method. The equilibrium yields of hydrogen, carbon monoxide, methane and coke as a function of H2O/MeOH ratio (0.0-10.0), O2/MeOH ratio (0.0-1.0), and temperature (200 掳C, 400 掳C, 600 掳C, 800 掳C) at 0.1 MPa are investigated. Methanol can be fully converted at any H2O/MeOH and O2/MeOH ratio in the condition range evaluated. Methane is the main product at low temperatures (200 掳C, 400 掳C), while hydrogen and carbon monoxide become dominant products with the increase of the temperature. 600 掳C is favorable for hydrogen production at which the highest hydrogen yield appears. Carbon monoxide yield increases monotonically with the increase of the temperature and shows its maximum at 800 掳C. An increase of the H2O/MeOH ratio leads to a preference for hydrogen production as well as an inhibition of the formation of carbon monoxide, methane and coke. The major contribution of adding oxygen is lowering the energy supply and suppressing the potential of coke formation at low H2O/MeOH ratio. However, the total oxidation of methanol tends to dominant in this case. For the purpose of producing hydrogen-rich gas, no oxygen addition is preferred. The favorable operation window is obtained as 600 掳C, H2O/MeOH ratio = 6.0-8.0 and O2/MeOH ratio = 0. Under this optimal condition, 2.77-2.84 mol/mol methanol hydrogen yield and 0.13-0.17 mol/mol methanol carbon monoxide yield with trace amount methane (0.0070-0.017 mol/mol methanol) can be achieved without the risk of carbon deposition.